dayup = 1.0 #假如不进步也不退步为1
dayfactor = 0.01 #每天进步或退步1%
for i  in range(365): #持续365天
    if i  %7 in [6,0]: #周六是6,周日是0
        dayup = dayup*(1-dayfactor) #每天退步factor
    else:
             dayup = dayup*(1+dayfactor) #每天进步factor
print("工作日的力量:{:.2f}".format(dayup)) #运行
